1
KCET 2023
MCQ (Single Correct Answer)
+1
-0

The point of intersection of the line $$x+1=\frac{y+3}{3}=\frac{-z+2}{2}$$ with the plane $$3 x+4 y+5 z=10$$ is

A
$$(2,-6,-4)$$
B
$$(2,6,-4)$$
C
$$(2,6,4)$$
D
$$(-2,6,-4)$$
2
KCET 2023
MCQ (Single Correct Answer)
+1
-0

If $$(2,3,-1)$$ is the foot of the perpendicular from $$(4,2,1)$$ to a plane, then the equation of the plane is

A
$$2 x+y+2 z-1=0$$
B
$$2 x-y+2 z=0$$
C
$$2 x+y+2 z-5=0$$
D
$$2 x-y+2 z+1=0$$
3
KCET 2023
MCQ (Single Correct Answer)
+1
-0

$$|\mathbf{a} \times \mathbf{b}|^2+|\mathbf{a} \cdot \mathbf{b}|^2=144$$ and $$|\mathbf{a}|=4$$, then $$|\mathbf{b}|$$ is equal to

A
3
B
8
C
4
D
12
4
KCET 2023
MCQ (Single Correct Answer)
+1
-0

If $$\mathbf{a}+2 \mathbf{b}+3 \mathbf{c}=0$$ and $$(\mathbf{a} \times \mathbf{b})+(\mathbf{b} \times \mathbf{c})+(\mathbf{c} \times \mathbf{a})=\lambda(\mathbf{b} \times \mathbf{c})$$, then the value of $$\lambda$$ is equal to

A
3
B
4
C
6
D
2
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