1
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Samhita faces a three-headed dragon. She wins a "Tactical medal" if she manages to defeat exactly one of the three heads.

The battle proceeds head-by-head under the following conditions:

  • The probability of defeating the first head is $\frac{\mathbf{1}}{\mathbf{3}}$.

  • After a win: if she defeats a head, the probability of defeating the next head is $\frac{2}{3}$.

  • After a loss: if she fails to defeat a head, the probability of defeating the next head is $\frac{\mathbf{1}}{\mathbf{4}}$.

What is the probability that Samhita earns the "Tactical medal"?

A

$\frac{23}{72}$

B

$\frac{5}{36}$

C

$\frac{17}{72}$

D

$\frac{19}{72}$

2
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int e^{2 x} \cos (5 x+3) d x= $$

A

$$ \frac{e^{2 x}}{29}[2 \sin (5 x+3)+5 \cos (5 x+3)]+C $$

B

$$ \frac{e^{2 x}}{29}[2 \sin (5 x+3)+5 \cos (5 x+3)]+C $$

C

$$ \frac{e^{2 x}}{29}[2 \cos (5 x+3)+5 \sin (5 x+3)]+C $$

D

$$ \frac{e^{2 x}}{29}[5 \cos (5 x+3)-2 \sin (5 x+3)]+C $$

3
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Given $A=\left(\begin{array}{ll}1 & 2 \\ 2 & 3\end{array}\right)$ and $f(x)=x^2-2 x-3$ then $f(A)$ is:

A

Identity matrix

B

Skew symmetric matrix

C

Null matrix

D

Symmetric Matrix

4
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The value of $\mathop {\lim }\limits_{x \to 3}\left[\frac{1}{x-3}+\frac{9 x}{27-x^3}\right]$ is:

A

$\frac{1}{2}$

B

1

C

2

D

0