The velocity of a body moving in a viscous medium is given by $v=\frac{A}{B+C}\left[1-e^{\frac{-t}{B}}\right]$ where $t$ is time; dimensions of $A$ and $C$ are
$\left[\mathrm{M}^0 \mathrm{~L}^1 \mathrm{~T}^0\right],\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^1\right]$
$\left[\mathrm{M}^0 \mathrm{~L}^1 \mathrm{~T}^1\right],\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^1\right]$
$\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^0\right],\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^{-1}\right]$
$\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^1\right],\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^1\right]$
A proton is moving along negative $X$ axis. If a uniform magnetic field is applied parallel to the positive $Z$ axis, then choose the correct answer from the following options;
The proton will experience magnetic force along positive Y direction and will move along a circular path in the XY plane
The proton will experience magnetic force along negative Y direction and will move along a circular path in the XY plane
The proton will experience magnetic force along positive Y direction and will move along a circular path in the XZ plane
The proton will experience magnetic force along negative Y direction and will move along a circular path in the XZ plane
4
2
1
3
The magnetic field at the centre of a wire loop formed by two semicircular wires of radii $r_1=3.14 \mathrm{~m}$ and $r_2=6.28 \mathrm{~m}$ and carrying a current of $\mathrm{I}=2 \mathrm{~A}$ is:
$6 \times 10^{-7} T$
$2 \times 10^{-7} T$
$3 \times 10^{-7} T$
$4 \times 10^{-7} T$
Two vessels A and B contain same mass of Oxygen and Hydrogen respectively at the same temperature. The volume of $B$ is twice that of $A$. The ratio of gas pressure in $A$ to that in $B$ is
1: 8
1:64
1:256
1:32
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