1
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

A proton is moving along negative $X$ axis. If a uniform magnetic field is applied parallel to the positive $Z$ axis, then choose the correct answer from the following options;

  1. The proton will experience magnetic force along positive Y direction and will move along a circular path in the XY plane

  2. The proton will experience magnetic force along negative Y direction and will move along a circular path in the XY plane

  3. The proton will experience magnetic force along positive Y direction and will move along a circular path in the XZ plane

  4. The proton will experience magnetic force along negative Y direction and will move along a circular path in the XZ plane

A

4

B

2

C

1

D

3

2
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The magnetic field at the centre of a wire loop formed by two semicircular wires of radii $r_1=3.14 \mathrm{~m}$ and $r_2=6.28 \mathrm{~m}$ and carrying a current of $\mathrm{I}=2 \mathrm{~A}$ is:

COMEDK 2026 Morning Shift Physics - Moving Charges and Magnetism Question 6 English
A

$6 \times 10^{-7} T$

B

$2 \times 10^{-7} T$

C

$3 \times 10^{-7} T$

D

$4 \times 10^{-7} T$

3
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two vessels A and B contain same mass of Oxygen and Hydrogen respectively at the same temperature. The volume of $B$ is twice that of $A$. The ratio of gas pressure in $A$ to that in $B$ is

A

1: 8

B

1:64

C

1:256

D

1:32

4
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two conducting spherical shells $A$ and $B$ of radii 4 cm and 6 cm respectively are placed with their centres 17 cm apart in air. Initially, sphere A was given a -20 nC charge while sphere B was uncharged. The spheres are then connected by a long thin conducting wire and allowed to reach electrostatic equilibrium. Assuming no charge is lost to the surroundings, the final charge on sphere A and the ratio of magnitude of electric field intensity at the surface of sphere $B$ to that of sphere $A$ is given by;

A

$-12 \mathrm{nC} ; \frac{2}{3}$

B

$-8 \mathrm{nC} ; \frac{3}{2}$

C

$-12 \mathrm{nC} ; \frac{3}{2}$

D

$-8 \mathrm{nC} ; \frac{2}{3}$