1
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The value of $\mathop {\lim }\limits_{x \to 3}\left[\frac{1}{x-3}+\frac{9 x}{27-x^3}\right]$ is:

A

$\frac{1}{2}$

B

1

C

2

D

0

2
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int \sqrt{2 a x-x^2} d x= $$

A

$$ \frac{x-a}{2} \sqrt{2 a x-x^2}+\frac{a^2}{2} \cos ^{-1}\left(\frac{x-a}{a}\right)+C $$

B

$$ \frac{a^2}{2} \sqrt{2 a x-x^2}+\frac{x-a}{2} \sin ^{-1}\left(\frac{x-a}{a}\right)+C $$

C

$$ \frac{x-a}{2} \sqrt{2 a x-x^2}+\frac{a^2}{2} \sin ^{-1}\left(\frac{x-a}{a}\right)+C $$

D

$$ \frac{a^2}{2} \sqrt{2 a x-x^2}+\frac{x-a}{2} \cos ^{-1}\left(\frac{x-a}{a}\right)+C $$

3
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Consider the following list of ordered pairs: $(1,0),(-2,-1),(7,-6),(-3,4)$ and $(0,2)$

Which of the following options correctly identifies only those pairs that are NOT elements of the relation $R=\{(x, y): y=1-|x| ; x, y \in \mathbb{Q}\}$ ?

A

$(1,0),(-2,-1)$

B

$(0,2),(-2,-1)$

C

$(-3,4),(0,2)$

D

$(-3,4),(7,-6)$

4
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Given $P=\left[\begin{array}{lll}2 & \boldsymbol{\alpha} & 1 \\ 1 & 2 & 2 \\ 1 & 3 & 3\end{array}\right]$ is the adjoint of a $3 \times 3$ matrix A and $|A|=3$, then the value of $\boldsymbol{\alpha}$ is:

A

7

B

-25

C

-8

D

-26