If the equilibrium constant for $\mathrm{N}_{2(g)}+\mathrm{O}_{2(g)} \rightleftharpoons 2 \mathrm{NO}_{(g)}$ is 49 The equilibrium constant for the reaction $N O_{(g)} \rightleftharpoons \frac{1}{2} N_{2(g)}+\frac{1}{2} O_{2(g)}$ is $\_\_\_\_$
0.143
24.5
49
0.020
Which of the following options represent the correct bond order?
$O_2^{+}< O_2^{-}< O_2$
$O_2< O_2^{-}< O_2^{+}$
$\mathrm{O}_2^{-}<\mathrm{O}_2<\mathrm{O}_2^{+}$
$O_2^{-}< O_2^{+}< O_2$
$$ \text { The decreasing order of reactivity towards electrophilic substitutions is: } $$

$I V>I>I I>I H$
$I I I>I>I I>I V$
$I>I I>I H>I V$
$I>I I I>I V>I I$
Identify the correct values to be plotted in the graph, the slope of which can be used to determine the activation energy of a reaction.
$\ln k $ vs $\frac{1}{T}$
$\ln k $ vs $T$
$\frac{\ln k}{T} $ vs $T$
$\frac{T}{\ln k}$ vs $\frac{1}{T}$
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