1
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the chord joining the points $(1,2)$ and $(2,-1)$ on a circle subtends an angle of $\frac{\pi}{4}$ at any point on its circumference, then the equation of such a circle is

A

$x^2+y^2+6 x-2 y+5=0$

B

$x^2+y^2-6 x-2 y+5=0$

C

$x^2+y^2-6 x+2 y+5=0$

D

$x^2+y^2+6 x+2 y+5=0$

2
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The equation of the circle which cuts all the three circles $4(x-1)^2+4(y-1)^2=1,4(x+1)^2+4(y-1)^2$ and $4(x+1)^2+4(y+1)^2=1$ orthogonally is

A

$4 x^2+4 y^2=49$

B

$4(x-1)^2+4(y+1)^2=1$

C

$(x-1)^2+(y+1)^2=4$

D

$4 x^2+4 y^2=7$

3
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the normal chord drawn at the point $\left(\frac{15}{2}, \frac{15}{\sqrt{2}}\right)$ to the parabola $y^2=15 x$ subtends an angle $\theta$ at the vertex of the parabola, then $\sin \frac{\theta}{3}+\cos \frac{2 \theta}{3}-\sec \frac{4 \theta}{3}=$

A

0

B

3

C

1

D

2

4
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If a tangent having slope $\frac{1}{3}$ to the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1(a>b)$ is a normal to the circle $(x+1)^2+(y+1)^2=1$, then $a^2$ lies in the interval

A

$\left(\frac{\sqrt{2}}{\sqrt{5}}, 2\right)$

B

$\left(\frac{2}{5}, 4\right)$

C

$\left(1, \frac{10}{9}\right)$

D

$(3,5)$