1
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The general solution of the differential equation $x y(y+2) d y+\left(y^3-1\right) d x=0$ is

A

$\log |x+2 y|+\frac{2}{\sqrt{3}} \tan ^{-1}\left(\frac{y-x}{\sqrt{3} x}\right)=C$

B

$\log |2 x-y|+\frac{2}{3} \tan ^{-1}\left(\frac{x-y}{\sqrt{3} x}\right)=C$

C

$\log |x y-x|+\frac{2}{\sqrt{3}} \tan ^{-1}\left(\frac{2 y+1}{\sqrt{3}}\right)=C$

D

$\log |x+y|+\frac{2}{3} \tan ^{-1}\left(\frac{x-2 y}{\sqrt{3 x}}\right)=C$

2
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The general solution of the differential equation $\left(1+\sin ^2 x\right) \frac{d y}{d x}+y \sin 2 x=\cos x+\sin ^2 x \cos x$ is

A

$(\sin 2 x) y=\sin ^2 x+C$

B

$\left(1+\sin ^2 x\right) y=\sin x-\frac{\sin ^3 x}{3}+C$

C

$\left(1+\sin ^2 x\right) y=\sin x+\frac{\sin ^3 x}{3}+C$

D

$(\sin 2 x) y=\sin x+\sin ^2 x+C$

3
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If force $=\frac{\alpha}{\operatorname{density}+\beta^3}$, then the dimensional formulae of $\alpha$ and $\beta$ are respectively

A

$\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right],\left[\mathrm{ML}^{-1 / 3} \mathrm{~T}^0\right]$

B

$\left[M^2 L^4 T^{-2}\right],\left[M^{1 / 3} L^{-1} T^0\right]$

C

$\left[\mathrm{M}^2 \mathrm{~L}^{-2} \mathrm{~T}^{-2}\right],\left[\mathrm{M}^{1 / 3} \mathrm{~L}^{-1} mathrm{~T}^0\right]$

D

$\left[\mathrm{M}^2 \mathrm{~L}^{-2} \mathrm{~T}^{-2}\right],\left[\mathrm{ML}^{-3} \mathrm{~T}^0\right]$

4
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The displacement $(x)$ and time $(t)$ graph of a particle moving along a straight line is shown in the figure. The average velocity of the particle in the time of 10 s is

AP EAPCET 2025 - 26th May Evening Shift Physics - Motion in a Straight Line Question 2 English

A

$2 \mathrm{~ms}^{-1}$

B

$4 \mathrm{~ms}^{-1}$

C

$6 \mathrm{~ms}^{-1}$

D

$8 \mathrm{~ms}^{-1}$