If $a$ and $b$ are arbitrary constants, then the differential equation corresponding to the family of curves $y=\tan (a x+b)$ is
$\left(1+x^2\right) y_2-2 y y_1+y=0$
$\left(1+y^2\right) y_2-2 y y_1^2=0$
$\left(1+x^2\right) y_2+2 y y_1^2=0$
$\left(1+y^2\right) y_2-2 y y_1^2+y=0$
The general solution of the differential equation $x y(y+2) d y+\left(y^3-1\right) d x=0$ is
$\log |x+2 y|+\frac{2}{\sqrt{3}} \tan ^{-1}\left(\frac{y-x}{\sqrt{3} x}\right)=C$
$\log |2 x-y|+\frac{2}{3} \tan ^{-1}\left(\frac{x-y}{\sqrt{3} x}\right)=C$
$\log |x y-x|+\frac{2}{\sqrt{3}} \tan ^{-1}\left(\frac{2 y+1}{\sqrt{3}}\right)=C$
$\log |x+y|+\frac{2}{3} \tan ^{-1}\left(\frac{x-2 y}{\sqrt{3 x}}\right)=C$
The general solution of the differential equation $\left(1+\sin ^2 x\right) \frac{d y}{d x}+y \sin 2 x=\cos x+\sin ^2 x \cos x$ is
$(\sin 2 x) y=\sin ^2 x+C$
$\left(1+\sin ^2 x\right) y=\sin x-\frac{\sin ^3 x}{3}+C$
$\left(1+\sin ^2 x\right) y=\sin x+\frac{\sin ^3 x}{3}+C$
$(\sin 2 x) y=\sin x+\sin ^2 x+C$
If force $=\frac{\alpha}{\operatorname{density}+\beta^3}$, then the dimensional formulae of $\alpha$ and $\beta$ are respectively
$\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right],\left[\mathrm{ML}^{-1 / 3} \mathrm{~T}^0\right]$
$\left[M^2 L^4 T^{-2}\right],\left[M^{1 / 3} L^{-1} T^0\right]$
$\left[\mathrm{M}^2 \mathrm{~L}^{-2} \mathrm{~T}^{-2}\right],\left[\mathrm{M}^{1 / 3} \mathrm{~L}^{-1} mathrm{~T}^0\right]$
$\left[\mathrm{M}^2 \mathrm{~L}^{-2} \mathrm{~T}^{-2}\right],\left[\mathrm{ML}^{-3} \mathrm{~T}^0\right]$
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