1
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The mean deviation from the median for the following data is

$$ \begin{array}{llllll} \hline x_1 & 9 & 3 & 7 & 2 & 5 \\ \hline f_1 & 1 & 6 & 2 & 8 & 4 \\ \hline \end{array} $$

A

$\frac{94}{21}$

B

$\frac{12}{7}$

C

$\frac{10}{7}$

D

$\frac{100}{21}$

2
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A company representative is distributing 5 identical samples of a product among 12 houses in a row such that each house gets at most one sample. The probability that no two consecutive house get one sample is

A

$\frac{7}{99}$

B

$\frac{5}{12}$

C

$\frac{4}{13}$

D

$\frac{5}{31}$

3
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0
  1. $A$ and $B$ are two independent events of a random experiment and $P(A)>P(B)$.

If the probability that both $A$ and $B$ occurs is $\frac{1}{6}$ and neither of them occurs is $\frac{1}{3}$, then the probability of the occurance of $B$ is

A

$\frac{1}{4}$

B

$\frac{1}{3}$

C

$\frac{1}{2}$

D

$\frac{3}{8}$

4
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two dice are thrown and the sum of the numbers appeared on the dice is noted. If $A$ is the event of getting a prime number as their sum and $B$ is the event of getting a number greater than 8 as their sum, then $P(A \cap \bar{B})=$

A

$\frac{1}{4}$

B

$\frac{13}{36}$

C

$\frac{2}{9}$

D

$\frac{5}{18}$