1
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If a real valued function

$$ f(x)=\left\{\begin{array}{cc} \log (1+[x]), & x \geq 0 \\ \sin ^{-1}[x], & -1 \leq x<0 \\ k([x]+|x|), & x<-1 \end{array}\right. $$

is continuous at $x=-1$, then $k=$

A

$-\pi / 2$

B

$-\pi$

C

$\pi$

D

$\pi / 2$

2
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $y=\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)$ and $\left(\frac{d^2 y}{d x^2}\right)_{x=2}=k$, then $25 k=$

A

$(-3)^2$

B

$(-2)^3$

C

3

D

$(-2)^5$

3
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $f(x)=x^{\sec ^{-1} x}$, then $f^{\prime}(2)=$

A

$\frac{2^{\pi / 3}}{6}(\pi-\sqrt{3} \log 2)$

B

$\frac{2^{\pi / 6}}{6}(\pi+\sqrt{3} \log 2)$

C

$\frac{2^{\pi / 3}}{6}(\pi+\sqrt{3} \log 2)$

D

$\frac{2^{\pi / 6}}{6}(\pi-\sqrt{3} \log 2)$

4
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $f(x)=\sec ^{-1}\left(\frac{1}{2 x^2-1}\right)$ and $g(x)=\tan ^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)$, then the derivative of $f(x)$ with respect to $g(x)$ is

A

$\frac{1+x^2}{4 \sqrt{1-x^2}}$

B

$\frac{\left(1-x^2\right)}{4 \sqrt{1+x^2}}$

C

$-\frac{4\left(1-x^2\right)}{\sqrt{1+x^2}}$

D

$-\frac{4\left(1+x^2\right)}{\sqrt{1-x^2}}$