1
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Two dice are thrown and the sum of the numbers appeared on the dice is noted. If $A$ is the event of getting a prime number as their sum and $B$ is the event of getting a number greater than 8 as their sum, then $P(A \cap \bar{B})=$

A

$\frac{1}{4}$

B

$\frac{13}{36}$

C

$\frac{2}{9}$

D

$\frac{5}{18}$

2
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A family consists of 8 persons. If 4 persons are chosen a random and they are found to be 2 men and 2 women, then the probability that there are equal number of men and women in that family is

A

$\frac{1}{5}$

B

$\frac{3}{7}$

C

$\frac{2}{5}$

D

$\frac{2}{7}$

3
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The number of trials conducted in a binomial distribution is 6 . If the difference between the mean and variance of this variate is $\frac{27}{8}$, then the probability of getting atmost 2 successes is

A

$\frac{106}{4^6}$

B

$\frac{144}{4^6}$

C

$\frac{126}{4^6}$

D

$\frac{154}{4^6}$

4
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $X \sim B(n, p)$ with mean $\mu$ and variance $\sigma^2$. If $\mu=2 \sigma^2$ and $\mu+\sigma^2=3$, then $P(X \leq 3)=$

A

$\frac{40}{49}$

B

$\frac{40}{43}$

C

$\frac{100}{101}$

D

$\frac{15}{16}$