1
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A family consists of 8 persons. If 4 persons are chosen a random and they are found to be 2 men and 2 women, then the probability that there are equal number of men and women in that family is

A

$\frac{1}{5}$

B

$\frac{3}{7}$

C

$\frac{2}{5}$

D

$\frac{2}{7}$

2
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The number of trials conducted in a binomial distribution is 6 . If the difference between the mean and variance of this variate is $\frac{27}{8}$, then the probability of getting atmost 2 successes is

A

$\frac{106}{4^6}$

B

$\frac{144}{4^6}$

C

$\frac{126}{4^6}$

D

$\frac{154}{4^6}$

3
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $X \sim B(n, p)$ with mean $\mu$ and variance $\sigma^2$. If $\mu=2 \sigma^2$ and $\mu+\sigma^2=3$, then $P(X \leq 3)=$

A

$\frac{40}{49}$

B

$\frac{40}{43}$

C

$\frac{100}{101}$

D

$\frac{15}{16}$

4
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $A(\cos \alpha, \sin \alpha), B(\sin \alpha,-\cos \alpha), C(1,2)$ are the vertices of a $\triangle A B C$, then the locus of its centroid is

A

$3\left(x^2+y^2\right)-2 x-4 y+1=0$

B

$x^2+y^2-2 x-4 y+1=0$

C

$x^2+y^2-2 x-4 y+3=0$

D

$2\left(x^2+y^2\right)-2 x-4 y+5=0$