1
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $f(x)=x^{\sec ^{-1} x}$, then $f^{\prime}(2)=$

A

$\frac{2^{\pi / 3}}{6}(\pi-\sqrt{3} \log 2)$

B

$\frac{2^{\pi / 6}}{6}(\pi+\sqrt{3} \log 2)$

C

$\frac{2^{\pi / 3}}{6}(\pi+\sqrt{3} \log 2)$

D

$\frac{2^{\pi / 6}}{6}(\pi-\sqrt{3} \log 2)$

2
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $f(x)=\sec ^{-1}\left(\frac{1}{2 x^2-1}\right)$ and $g(x)=\tan ^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right)$, then the derivative of $f(x)$ with respect to $g(x)$ is

A

$\frac{1+x^2}{4 \sqrt{1-x^2}}$

B

$\frac{\left(1-x^2\right)}{4 \sqrt{1+x^2}}$

C

$-\frac{4\left(1-x^2\right)}{\sqrt{1+x^2}}$

D

$-\frac{4\left(1+x^2\right)}{\sqrt{1-x^2}}$

3
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the tangent of the curve $x y+a x+b y=0$ at $(1,1)$ makes an angle $\tan ^{-1} 2$ with $X$-axis, then $\frac{a b}{a+b}=$

A

1

B

2

C

3

D

4

4
AP EAPCET 2025 - 26th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the displacement $S$ of a particle travelling along a straight line in $t$ seconds is given by $S=2 t^3+2 t^2-2 t-3$, then the time taken (in second) by the particle to change its direction is

A

$\frac{1}{3}$

B

2

C

3

D

$\frac{1}{2}$