1
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_0^{\pi / 4} \frac{\sec x}{1+2 \sin ^2 x} d x= $$

A
$\frac{1}{3} \log (\sqrt{2}+1)+\frac{\pi \sqrt{2}}{12}$
B
$\frac{2}{3} \log (\sqrt{2}+1)+\frac{\pi \sqrt{2}}{6}$
C
$\frac{1}{6} \log (\sqrt{2}-1)+\frac{\pi}{12}$
D
$\frac{1}{4} \log (\sqrt{2}-1)-\frac{\pi \sqrt{3}}{6}$
2
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\int x^4(\log x)^3 d x=x^5\left[A(\log x)^3\right]$ $\left.+B(\log x)^2+C \log x+D\right]+k$, then $A+B+C+5 D=$

A
$\frac{2}{25}$
B
$\frac{8}{25}$
C
$\frac{12}{125}$
D
$\frac{16}{125}$
3
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \lim\limits_{n \rightarrow \infty}\left[\frac{1}{n^2} \sec ^2 \frac{1}{n^2}+\frac{2}{n^2} \sec ^2 \frac{4}{n^2}+\ldots \ldots+\frac{1}{n} \sec ^2 1\right]= $$

A
$\frac{1}{2} \sec (1)$
B
$\frac{1}{2} \operatorname{cosec}(1)$
C
$\tan (1)$
D
$\frac{1}{2} \tan (1)$
4
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int\limits_2^5 \sqrt{\frac{5-x}{x-2}} d x= $$

A
$\pi$
B
$\frac{\pi}{2}$
C
$\frac{3 \pi}{2}$
D
$\frac{\pi}{4}$
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