1
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $A$ is a non-singular matrix such that $(A-2 I)$ $(A-3 I)=0$, then $\frac{1}{5} A+\frac{6}{5} A^{-1}=$

A
0
B
I
C
2I
D
3I
2
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $A$ be a matrix such that $A B$ is a scalar matrix, where $B=\left[\begin{array}{ll}1 & 2 \\ 0 & 3\end{array}\right]$ and $\operatorname{det}(3 A)=27$. Then, $3 A^{-1}+A^2=$

A
$\left[\begin{array}{cc}4 & -6 \\ 0 & 2\end{array}\right]$
B
$\left[\begin{array}{cc}9 & -4 \\ 0 & 3\end{array}\right]$
C
$\left[\begin{array}{cc}10 & -6 \\ 0 & 2\end{array}\right]$
D
$\left[\begin{array}{cc}10 & -6 \\ 0 & 4\end{array}\right]$
3
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $A$ is a symmetric matrix with real entries, then

A
$A^{-1}$ is symmetric, if it exists
B
$A^{-1}$ always exists and is symmetric
C
$A^{-1}$ is skew-symmetric, if it exists
D
$A^{-1}$ always exists and is skew-symmetric
4
TS EAMCET 2023 (Online) 12th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$\operatorname{Arg}\left(\sin \frac{6 \pi}{5}+i\left(1+\cos \frac{6 \pi}{5}\right)\right)=$

A
$\frac{5 \pi}{6}$
B
$\frac{6 \pi}{5}$
C
$\frac{2 \pi}{5}$
D
$\frac{9 \pi}{10}$
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