1
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If M denotes the midpoint of the line joining A$(4, 5, -10)$ and B$(-1, 2, 1)$, then the equation of the plane through M and perpendicular to AB is:
A
$\bar{r} \cdot \left(-5\hat{i} - 3\hat{j} + 11\hat{k}\right) + \dfrac{135}{2} = 0$
B
$\bar{r} \cdot \left(\dfrac{3}{2}\hat{i} + \dfrac{7}{2}\hat{j} - \dfrac{9}{2}\hat{k}\right) + \dfrac{135}{2} = 0$
C
$\bar{r} \cdot \left(4\hat{i} + 5\hat{j} - 10\hat{k}\right) + 4 = 0$
D
$\bar{r} \cdot \left(-\hat{i} + 2\hat{j} + \hat{k}\right) + 4 = 0$
2
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The difference between the maximum value and the minimum value of the objective function $z = 3x + y$ subject to the constraints $2x + 3y \leq 6$, $x + y \geq 1$, $x \geq 0$, $y \geq 0$ is....
A
$7$
B
$3$
C
$8$
D
$1$
3
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
A random variable $X \sim B(n, p)$ follows a binomial distribution with $n = 6$. If $9P(X = 4) = P(X = 2)$, then the probability of success $p$ is..
A
$0.125$
B
$0.75$
C
$0.25$
D
$0.375$
4
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Let X be a continuous random variable with the probability density function(p.d.f.) given by
$f(x) = \begin{cases} kx, & 0 \leq x < 1 \\ k, & 1 \leq x < 2 \\ -kx + 3k, & 2 \leq x < 3 \\ 0, & \text{otherwise} \end{cases}$
$P(2 < X \leq 3) = \cdots$
A
$\dfrac{1}{2}$
B
$\dfrac{1}{3}$
C
$\dfrac{1}{4}$
D
$\dfrac{1}{5}$

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