MHT CET 2026 20th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 20th April Morning Shift

MCQ (Single Correct Answer)

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Two identical photocathodes receive light of frequencies $n_1$ and $n_2$. If the velocities of the emitted photoelectrons of mass m are $V_1$ and $V_2$ respectively, then ($h$ = Planck's constant)

$V_1 + V_2 = \left[\dfrac{2h}{m}(n_1 + n_2)\right]^{\frac{1}{2}}$

$V_1 - V_2 = \left[\dfrac{2h}{m}(n_1 - n_2)\right]^{\frac{1}{2}}$

$V_1^2 + V_2^2 = \dfrac{2h}{m}(n_1 + n_2)$

$V_1^2 - V_2^2 = \dfrac{2h}{m}(n_1 - n_2)$

MHT CET 2026 20th April Morning Shift

MCQ (Single Correct Answer)

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An electron in the hydrogen atom jumps from $n^{th}$ energy state to the ground state. The wavelength so emitted illuminates a photosensitive material having work function $2.65$ eV. If the maximum kinetic energy of the emitted photoelectrons is $10.1$ eV, then the value of '$n$' is

$2$

$3$

$4$

$5$

MHT CET 2026 20th April Morning Shift

MCQ (Single Correct Answer)

-0

The angular momentum of an electron in Bohr's hydrogen atom having energy $(-0.544)$ eV is
($h$ = Planck's constant)

$\dfrac{h}{\pi}$

$\dfrac{3h}{\pi}$

$\dfrac{5h}{2\pi}$

$\dfrac{7h}{2\pi}$