1
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Light of wavelength $580$ nm is incident normally on a slit of width '$a$'. The distance between slit and screen is $2.5$ m and the distance of the second order maximum from the centre of the screen is $14.5$ mm in a diffraction pattern. The value of '$a$' is
A
$0.12 \times 10^{-3}\,\text{m}$
B
$0.25 \times 10^{-3}\,\text{m}$
C
$0.36 \times 10^{-3}\,\text{m}$
D
$0.50 \times 10^{-3}\,\text{m}$
2
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
In an interference experiment, the $m^{th}$ bright fringe for light of wavelength $\lambda_1$ coincides with the $n^{th}$ dark fringe for light of wavelength $\lambda_2$ . The ratio $\dfrac{\lambda_2}{\lambda_1}$ is
A
$\dfrac{m}{n-1}$
B
$\dfrac{m}{(2n-1)}$
C
$\dfrac{2m}{(2n-1)}$
D
$\dfrac{2m}{(2n+1)}$
3
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
In a biprism experiment, the distance between $4^{th}$ and $13^{th}$ bright band on the same side is '$y$' when light of wavelength $6000$ Å is used. For a light of wavelength '$\lambda$' the distance between $6^{th}$ and $16^{th}$ bright band on the same side is again '$y$'. The value of '$\lambda$' in Å units is
A
$6500$
B
$6300$
C
$5400$
D
$4800$
4
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
The proton and $\alpha$ - particle are accelerated through same potential difference. Then the ratio of the de-Broglie wavelength of proton and $\alpha$ - particle is (mass of $\alpha$-particle is $4$ times mass of proton, charge of $\alpha$-particle is $2$ times charge of proton)
A
$3\sqrt{3}$
B
$3\sqrt{2}$
C
$2\sqrt{3}$
D
$2\sqrt{2}$

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