1
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $3\sin^{-1}\left(\dfrac{2x}{1 + x^2}\right) - 4\cos^{-1}\left(\dfrac{1 - x^2}{1 + x^2}\right) + 2\tan^{-1}\left(\dfrac{2x}{1 - x^2}\right) = \dfrac{\pi}{3}$ then $x = ?$
A
$\sqrt{3}$
B
$1$
C
$\dfrac{1}{\sqrt{3}}$
D
$-1$
2
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $2\sin^{-1}x - 3\cos^{-1}x = 4$, then $2\sin^{-1}x + 3\cos^{-1}x =$
A
$\dfrac{6\pi - 4}{5}$
B
$\dfrac{6\pi + 4}{5}$
C
$\dfrac{5\pi - 4}{6}$
D
$\dfrac{5\pi + 4}{6}$
3
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \dfrac{2x - 1}{x + 5}$, $x \neq -5$ then $f^{-1}(x)$ is equal to
A
$\dfrac{x + 5}{2x - 1}$, $x \neq \dfrac{1}{2}$
B
$\dfrac{5x + 1}{2 - x}$, $x \neq 2$
C
$\dfrac{5x - 1}{2 - x}$, $x \neq 2$
D
$\dfrac{x - 5}{2x + 1}$, $x \neq -\dfrac{1}{2}$
4
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If the function $f(x)$ defined by $f(x) = \begin{cases} ax + 1 & \text{if } x \leq 3 \\ bx + 3 & \text{if } x > 3 \end{cases}$ is continuous at $x = 3$, then $(a - b) =$ ..........
A
$\dfrac{2}{3}$
B
$\dfrac{3}{2}$
C
$2$
D
$3$

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