The displacement of a particle varies with time according to the relation
$x = a\sin\omega t + b\cos\omega t$

For a particle executing S.H.M., the potential energy is $n$ times the kinetic energy when its displacement from mean position is $\left(\dfrac{2\sqrt{2}}{3}\right)A$, where $A$ is the amplitude of S.H.M. The value of $n$ is

A particle is performing S.H.M. about $x = 0$, with an amplitude $a$ and time period $T$. The speed of the particle at $x = \dfrac{a}{3}$ will be

Two sound waves each of wavelength $\lambda$ and same amplitude $A$ interfere at point $Q$. If the path difference is $\dfrac{\lambda}{4}$, the amplitude of the resultant wave at point $Q$ is $\left[\sin\dfrac{\pi}{2} = 1, \cos\dfrac{\pi}{2} = 0\right]$