1
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $A = \begin{bmatrix} 1 & -5 \\ -2 & 4 \end{bmatrix}$, then $A^{-1} =$
A
$-\dfrac{1}{6}\begin{bmatrix} -4 & 5 \\ 2 & -1 \end{bmatrix}$
B
$\dfrac{1}{14}\begin{bmatrix} -1 & 5 \\ 2 & -4 \end{bmatrix}$
C
$\dfrac{1}{14}\begin{bmatrix} 4 & 5 \\ 2 & 1 \end{bmatrix}$
D
$-\dfrac{1}{6}\begin{bmatrix} 4 & 5 \\ 2 & 1 \end{bmatrix}$
2
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Let $A = \begin{bmatrix} 3 & 1 & 2 \\ 1 & 2 & 0 \\ 1 & 1 & 4 \end{bmatrix}$ and $pC_{11} + 4C_{21} - 5C_{32} = -2$, where $C_{ij}$ denotes the cofactor of an element $a_{ij}$ of matrix $A$, then the value of $p$ is :
A
$-2$
B
$2$
C
$4$
D
$3$
3
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $3\sin^{-1}\left(\dfrac{2x}{1 + x^2}\right) - 4\cos^{-1}\left(\dfrac{1 - x^2}{1 + x^2}\right) + 2\tan^{-1}\left(\dfrac{2x}{1 - x^2}\right) = \dfrac{\pi}{3}$ then $x = ?$
A
$\sqrt{3}$
B
$1$
C
$\dfrac{1}{\sqrt{3}}$
D
$-1$
4
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $2\sin^{-1}x - 3\cos^{-1}x = 4$, then $2\sin^{-1}x + 3\cos^{-1}x =$
A
$\dfrac{6\pi - 4}{5}$
B
$\dfrac{6\pi + 4}{5}$
C
$\dfrac{5\pi - 4}{6}$
D
$\dfrac{5\pi + 4}{6}$

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