MHT CET 2026 16th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 16th April Morning Shift

MCQ (Single Correct Answer)

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A closed pipe containing liquid showed a pressure $P_1$ by gauge. When the valve was opened, pressure was reduced to $P_2$. The speed of water flowing out of the pipe is ($\varrho$=density of water)

$\left[\dfrac{(P_1 - P_2)}{\varrho}\right]^{\frac{1}{2}}$

$\left[\dfrac{2(P_1 - P_2)}{\varrho}\right]^{\frac{1}{2}}$

$\left[\dfrac{(P_2 - P_1)}{\varrho}\right]^{\frac{1}{2}}$

$\left[\dfrac{2(P_2 - P_1)}{\varrho}\right]^{\frac{1}{2}}$

MHT CET 2026 16th April Morning Shift

MCQ (Single Correct Answer)

-0

Water flows through a horizontal pipe at a speed 'V'. Internal diameter of the pipe is 'd'. If the water is emerging at a speed '$V_1$' then the diameter of the nozzle is

$\text{d}\sqrt{\dfrac{\text{V}}{\text{V}_1}}$

$\text{d}\sqrt{\dfrac{\text{V}_1}{\text{V}}}$

$\dfrac{\text{dV}}{\text{V}_1}$

$\dfrac{\text{dV}_1}{\text{V}}$

MHT CET 2026 16th April Morning Shift

MCQ (Single Correct Answer)

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A liquid is at rest in a container. In a sphere of influence, the liquid molecule at its centre is

attracted by other molecules in the sphere of influence.

attracted by other molecules outside sphere of influence.

repelled by other molecules outside the sphere of influence.

repelled by other molecules in the sphere of influence.

MHT CET 2026 16th April Morning Shift

MCQ (Single Correct Answer)

-0

Rate of flow of heat through a cylindrical rod is '$H_1$'. The temperature at the ends of the rod are $T_1$ and $T_2$. If all the dimensions of the rod become double and the temperature difference remains the same and if the rate of flow of heat becomes '$H_2$' then $H_2 =$

$\dfrac{\text{H}_1}{2}$

$4\text{H}_1$

$2\text{H}_1$

$\dfrac{\text{H}_1}{4}$

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