1
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Let $\vec{P} = \hat{i} + \hat{j} + \hat{k}$ and $\vec{Q} = -(\hat{i} + \hat{j} + \hat{k})$. The angle between $(\vec{P} - \vec{Q})$ and $\vec{P}$ is
A
$90^\circ$
B
$60^\circ$
C
$0^\circ$
D
$30^\circ$
2
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A ball is released from height 'h' which makes perfectly elastic collision with ground. The frequency of periodic vibratory motion is (g=acceleration due to gravity)
A
$\dfrac{1}{2}\sqrt{\dfrac{g}{2h}}$
B
$\dfrac{1}{2}\sqrt{\dfrac{2h}{g}}$
C
$\dfrac{1}{2\pi}\sqrt{\dfrac{g}{2h}}$
D
$\dfrac{1}{2\pi}\sqrt{\dfrac{2h}{g}}$
3
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Two boys are standing at points A and B on ground where distance AB = a. The boy at point B starts running perpendicular to line AB with velocity '$V_1$'. The boy at point A starts running simultaneously with velocity 'V' and catches the other boy in time 't'. The value of 't' is
A
$\left[\dfrac{a^2}{(V^2 - V_1^2)}\right]^{\frac{1}{2}}$
B
$\left[\dfrac{a^2}{(V_1^2 - V^2)}\right]^{\frac{1}{2}}$
C
$\left[\dfrac{a^2}{(V^2 - V_1^2)}\right]$
D
$\left[\dfrac{a^2}{(V_1^2 - V^2)}\right]$
4
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A particle is moving with constant angular acceleration $4\,\text{rad/s}^2$ in circular path. At what time the magnitudes of its tangential acceleration and centripetal acceleration will be equal ?
A
$0.2$ s
B
$0.4$ s
C
$0.5$ s
D
$0.6$ s

MHT CET Papers

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