MHT CET 2026 16th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 16th April Morning Shift

MCQ (Single Correct Answer)

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The masses and radii of the earth and moon are $M_1$, $R_1$ and $M_2$, $R_2$ and respectively, Their centres are at a distance 'd' apart. The minimum speed with which body of mass 'm' should be projected from a distance $2d/3$ from the centre of $M_1$ so as to escape to infinity is

$\sqrt{\dfrac{6G}{d}(2M_1 + M_2)}$

$\sqrt{\dfrac{6G}{d}(M_1 - 2M_2)}$

$\sqrt{\dfrac{3G}{d}(M_1 + 2M_2)}$

$\sqrt{\dfrac{8G}{d}(M_1 - 2M_2)}$

MHT CET 2026 16th April Morning Shift

MCQ (Single Correct Answer)

-0

A rectangular block of mass 'm' and cross-sectional area 'A' floats on a liquid of density '$\varrho$'. It is given a small vertical displacement from equilibrium, it starts oscillating with frequency (g=acceleration due to gravity)

$2\pi\sqrt{\dfrac{\text{m}}{\text{A}\varrho\text{g}}}$

$2\pi\sqrt{\dfrac{\text{A}\varrho\text{g}}{\text{m}}}$

$\dfrac{1}{2\pi}\sqrt{\dfrac{\text{A}\varrho\text{g}}{\text{m}}}$

$\dfrac{1}{2\pi}\sqrt{\dfrac{\text{m}}{\text{A}\varrho\text{g}}}$

MHT CET 2026 16th April Morning Shift

MCQ (Single Correct Answer)

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A closed pipe containing liquid showed a pressure $P_1$ by gauge. When the valve was opened, pressure was reduced to $P_2$. The speed of water flowing out of the pipe is ($\varrho$=density of water)

$\left[\dfrac{(P_1 - P_2)}{\varrho}\right]^{\frac{1}{2}}$

$\left[\dfrac{2(P_1 - P_2)}{\varrho}\right]^{\frac{1}{2}}$

$\left[\dfrac{(P_2 - P_1)}{\varrho}\right]^{\frac{1}{2}}$

$\left[\dfrac{2(P_2 - P_1)}{\varrho}\right]^{\frac{1}{2}}$

MHT CET 2026 16th April Morning Shift

MCQ (Single Correct Answer)

-0

Water flows through a horizontal pipe at a speed 'V'. Internal diameter of the pipe is 'd'. If the water is emerging at a speed '$V_1$' then the diameter of the nozzle is

$\text{d}\sqrt{\dfrac{\text{V}}{\text{V}_1}}$

$\text{d}\sqrt{\dfrac{\text{V}_1}{\text{V}}}$

$\dfrac{\text{dV}}{\text{V}_1}$

$\dfrac{\text{dV}_1}{\text{V}}$

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