1
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Let $(\bar{p} \wedge \bar{q})$ denote the angle between $\bar{p}$ and $\bar{q}$. If $\bar{a} + \bar{b} + \bar{c} = \bar{0}, |\bar{a}| = 7, |\bar{b}| = 5$ and $|\bar{c}| = 3$ then (take $\pi = \dfrac{22}{7}$)
A
$\sin(\bar{b} \wedge \bar{c}) = \dfrac{1}{2}$
B
$\cos(\bar{a} \wedge \bar{c}) = -\dfrac{\pi}{4}$
C
$\cos(\bar{b} \wedge \bar{c}) = -\dfrac{1}{2}$
D
$\sin(\bar{a} \wedge \bar{c}) = \dfrac{\pi}{4}$
2
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If the lines $\dfrac{x-5}{5m+2} = \dfrac{2-y}{5} = \dfrac{1-z}{-1}$ and $x = \dfrac{2y+1}{4m} = \dfrac{1-z}{-3}$ are perpendicular to each other, then the value of m is ...
A
$1$
B
$0$
C
$2$
D
$-1$
3
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
For the line $\dfrac{x+1}{1} = \dfrac{y-2}{2} = \dfrac{z+3}{3}$, identify the incorrect statement among the following.
A
It can be represented by equation $\dfrac{x+2}{1} = \dfrac{y}{2} = \dfrac{z+6}{3}$
B
It lies in the plane $x - 2y + z + 8 = 0$
C
It is perpendicular to the plane $x - 2y + z = 0$
D
It passes through point $(0, 4, 0)$.
4
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The direction cosines of a line which is perpendicular to the lines $\dfrac{x-7}{2} = \dfrac{y+17}{-3} = \dfrac{z-6}{1}$ and $\dfrac{x+5}{1} = \dfrac{y+3}{2} = \dfrac{z-6}{-2}$ are...
A
$\dfrac{\pm 4}{3\sqrt{10}}, \dfrac{\mp 5}{3\sqrt{10}}, \dfrac{\pm 7}{3\sqrt{10}}$
B
$\dfrac{\pm 4}{3\sqrt{10}}, \dfrac{\pm 5}{3\sqrt{10}}, \dfrac{\mp 7}{3\sqrt{10}}$
C
$\dfrac{\mp 4}{3\sqrt{10}}, \dfrac{\pm 5}{3\sqrt{10}}, \dfrac{\pm 7}{3\sqrt{10}}$
D
$\dfrac{\pm 4}{3\sqrt{10}}, \dfrac{\pm 5}{3\sqrt{10}}, \dfrac{\pm 7}{3\sqrt{10}}$

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