1
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The dual of the converse of the inverse of the logical statement $p \to (q \to r)$ is equivalent to...
A
$\sim [p \vee (r \to q)]$
B
$p \vee (r \to q)$
C
$\sim [p \vee (q \to r)]$
D
$p \vee (q \to r)$
2
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The statements p, q and r have truth values True, False and False respectively. The truth values of a logical statement $[\sim(p \wedge \sim q) \vee (q \vee \sim r)]$ and its dual are, respectively.....
A
True, True
B
True, False
C
False, True
D
False, False
3
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
In $\triangle ABC$ with usual notations, if $1 + \tan\left(\dfrac{A}{2}\right)\tan\left(\dfrac{B}{2}\right) = \dfrac{k}{s}$ (where $s$ is the semi-perimeter), then the value of $k$ is...
A
$2$
B
$a + b - c$
C
$a + b$
D
$s - c$
4
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Let $A = \begin{bmatrix} 2k-1 & 1 & 1 \\ 0 & 2k-1 & 1 \\ 0 & 0 & 2k-1 \end{bmatrix}$ and $B = \begin{bmatrix} 0 & 2k-1 & 1 \\ 1-2k & 0 & k \\ -1 & -k & 0 \end{bmatrix}$ where k is a real number. If $\det(\text{adj} A) + \det(\text{adj} B) = 11^6$, then the value of $k - 5$ is equal to...
A
$1$
B
$2$
C
$4$
D
$6$

MHT CET Papers

All year-wise previous year question papers