MHT CET 2026 15th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 15th April Morning Shift

MCQ (Single Correct Answer)

-0

A circular coil of 'N' turns and diameter 'd' carries current 'I'. It is unwound and rewound to make another coil of diameter '2d', current 'I' remaining the Same. The ratio of magnetic moments of the new coil to the original coil is

$2:1$

$1:1$

$1:2$

$4:1$

MHT CET 2026 15th April Morning Shift

MCQ (Single Correct Answer)

-0

Lorentz magnetic force is acting on a particle of charge $q$ moving with velocity $\vec{V}$ in magnetic field $\vec{B}$. The work done by this force on the charged particle is

zero

$\vec{V} \times \vec{B}$

$\vec{V} \times \vec{V}$

$q(\vec{V} \times \vec{B})$

MHT CET 2026 15th April Morning Shift

MCQ (Single Correct Answer)

-0

A coil of 'n' turns and resistance $R\,\Omega$ is connected in series with a resistance $R/4$. The combination is moved for time 't' second through flux $\Phi_1$ to $\Phi_2$. The induced current in the circuit is

$\dfrac{4n(\Phi_1 - \Phi_2)}{5RT}$

$\dfrac{5n^2(\Phi_1 - \Phi_2)}{4RT}$

$\dfrac{2n(\Phi_1 - \Phi_2)}{3RT}$

$\dfrac{3n(\Phi_1 - \Phi_2)}{4RT}$

MHT CET 2026 15th April Morning Shift

MCQ (Single Correct Answer)

-0

The coefficient of mutual induction is $3$H and induced e.m.f. across secondary is $4$ kV. Current in primary is reduced from $7$A to $2$A. The time required for the change of current is

$3.75 \times 10^{-3}$ s

$2.5 \times 10^{-3}$ s

$4.5 \times 10^{-3}$ s

$3.5 \times 10^{-3}$ s

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