1
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The value of f(0) so that the function $f(x) = \dfrac{(256 - 8x)^{\frac{1}{4}} - 4}{16 - 4(64 + 3x)^{\frac{1}{3}}}$, $x \neq 0$ is continuous at $x = 0$, is
A
$-\dfrac{1}{8}$
B
$\dfrac{1}{8}$
C
$\dfrac{1}{64}$
D
$8$
2
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The derivative of $\sin\left(\log\left(\dfrac{x+3}{x}\right)\right)$ is
A
$\dfrac{3}{x+3}\cos\left(\log\left(\dfrac{x+3}{x}\right)\right)$
B
$\dfrac{3}{x(x+3)}\cos\left(\log\left(\dfrac{x+3}{x}\right)\right)$
C
$\dfrac{-3}{x(x+3)}\cos\left(\log\left(\dfrac{x+3}{x}\right)\right)$
D
$\dfrac{-1}{x(x+3)}\cos\left(\log\left(\dfrac{x+3}{x}\right)\right)$
3
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $e^y + xy = e$, then the ordered pair $\left(\dfrac{\text{d}y}{\text{d}x}, \dfrac{\text{d}^2 y}{\text{d}x^2}\right)$ at $x = 0$ is equal to
A
$\left(\dfrac{1}{e}, \dfrac{-1}{e^2}\right)$
B
$\left(\dfrac{-1}{e}, \dfrac{1}{e^2}\right)$
C
$\left(\dfrac{1}{e}, \dfrac{1}{e^2}\right)$
D
$\left(\dfrac{-1}{e}, \dfrac{-1}{e^2}\right)$
4
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The surface area of a spherical ball is increasing at the rate of $4\pi\ \text{cm}^2$/second. The rate at which the radius is increasing when the surface area is $16\pi\ \text{cm}^2$ is
A
$0.5$ cm/second
B
$0.25$ cm/second
C
$0.125$ cm/second
D
$1$ cm/second

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