1
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $A = \begin{bmatrix} 3 & 1 \\ -1 & 2 \end{bmatrix}$, $C = \begin{bmatrix} 7 & 3 \\ 0 & 6 \end{bmatrix}$ and $AB = C$, then the inverse of matrix B is
A
$\dfrac{1}{42}\begin{bmatrix} 3 & 0 \\ -1 & 2 \end{bmatrix}$
B
$\dfrac{1}{6}\begin{bmatrix} 3 & 0 \\ -1 & 2 \end{bmatrix}$
C
$\dfrac{1}{42}\begin{bmatrix} 6 & 3 \\ -1 & 2 \end{bmatrix}$
D
$\dfrac{1}{6}\begin{bmatrix} 7 & 3 \\ -1 & 3 \end{bmatrix}$
2
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The element in the third row and the second column in the inverse matrix of a matrix $\begin{bmatrix} 1 & 3 & 3 \\ 3 & 1 & 3 \\ 3 & 3 & 4 \end{bmatrix}$ is
A
$\dfrac{3}{2}$
B
$\dfrac{2}{3}$
C
$\dfrac{-3}{2}$
D
$\dfrac{-2}{3}$
3
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $y = \tan^{-1}\sqrt{\dfrac{1 + \sin 2x}{1 - \sin 2x}}$, then $\dfrac{\text{d}y}{\text{d}x}$ at $x = \dfrac{\pi}{6}$ is
A
$0$
B
$1$
C
$\dfrac{1}{2}$
D
$\dfrac{\sqrt{3}}{2}$
4
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The value of $\tan^{-1}\left(\dfrac{\cos\left(\frac{19\pi}{4}\right) - 1}{\sin\left(\frac{\pi}{4}\right)}\right)$ is equal to
A
$-\dfrac{\pi}{4}$
B
$-\dfrac{5\pi}{12}$
C
$-\dfrac{3\pi}{8}$
D
$-\dfrac{4\pi}{9}$

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