1
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The dual of the statement pattern $(p \wedge \sim q) \longrightarrow (q \wedge \sim p)$ is equivalent to
A
$\sim(p \rightarrow q) \wedge (q \rightarrow p)$
B
$(p \rightarrow q) \wedge \sim(q \rightarrow p)$
C
$(\sim p \rightarrow q) \wedge (q \rightarrow p)$
D
$(q \rightarrow p) \vee (\sim p \rightarrow \sim q)$
2
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Negation of the statement "If an integer is greater than 4 and less than 5, then it is a multiple of 3", is
A
An integer is not greater than 4 but less than 5 and it is a multiple of 3.
B
If an integer is not greater than 4 and less than 5 then it is not a multiple of 3.
C
An integer is greater than 4 and less than 5 but it is not a multiple of 3.
D
An integer is not greater than 4 and not less than 5 but it is not a multiple of 3.
3
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
In a triangle ABC, with the usual notations, $\angle B = \dfrac{\pi}{3}$, $\angle C = \dfrac{\pi}{4}$. If D divides BC internally in the ratio 1:3, then $\dfrac{\sin \angle BAD}{\sin \angle CAD} =$
A
$\dfrac{1}{3}$
B
$\dfrac{1}{\sqrt{3}}$
C
$\dfrac{1}{\sqrt{6}}$
D
$\sqrt{\dfrac{2}{3}}$
4
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Let $P_1$, $P_2$, $P_3$ be the altitudes of a triangle ABC from the vertices A, B, C respectively. If $\triangle$ denotes the area of the triangle and s is the semi-perimeter of the triangle, then $\dfrac{\cos A}{P_1} + \dfrac{\cos B}{P_2} + \dfrac{\cos C}{P_3} =$
A
$R$
B
$\dfrac{1}{R}$
C
$R^2$
D
$\dfrac{1}{R^2}$

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