1
MHT CET 2026 11th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Let $A(2,3,0)$, $B(0,3,2)$ and $C(4,0,3)$ be vertices of a triangle, then the area of the triangle is
A
$\dfrac{\sqrt{171}}{2} \text{ sq. units}$
B
$\dfrac{\sqrt{172}}{2} \text{ sq. units}$
C
$\dfrac{\sqrt{173}}{2} \text{ sq. units}$
D
$\dfrac{\sqrt{174}}{2} \text{ sq. units}$
2
MHT CET 2026 11th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If D and E are the midpoints of the sides BA and BC of triangle ABC, then $\overline{AE} + \overline{DC} = $
A
$\overline{AC}$
B
$\dfrac{3}{2} \overline{BC}$
C
$\dfrac{3}{2} \overline{AC}$
D
$\dfrac{1}{2} \overline{AC}$
3
MHT CET 2026 11th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If the points $(1, 1, \mu)$ and $(-3, 0, 1)$ are equidistant from the plane $\vec{r} \cdot (3\hat{i} + 4\hat{j} - 12\hat{k}) + 13 = 0$, then the value of $\mu$ are
A
$1, \dfrac{-7}{3}$
B
$1, \dfrac{7}{3}$
C
$-1, \dfrac{7}{3}$
D
$1, \dfrac{3}{7}$
4
MHT CET 2026 11th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If the lines $\dfrac{x-1}{2} = \dfrac{y+1}{3} = \dfrac{z-1}{4}$ and $\dfrac{x-2}{1} = \dfrac{y+m}{2} = \dfrac{z-2}{1}$ intersect each other, then the value of $m$ is....
A
$1$
B
$2$
C
$-1$
D
$4$

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