MHT CET 2026 11th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 11th April Morning Shift

MCQ (Single Correct Answer)

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The particular solution of the differential equation $xdy + 2ydx = 0$, when $x = 2$ and $y = 1$ is

$x\sqrt{y} = 2$

$x\sqrt{y} = -2$

$\sqrt{x} y = 2$

$x\sqrt{y} = 1$

MHT CET 2026 11th April Morning Shift

MCQ (Single Correct Answer)

-0

The differential equation representing the family of curves $x \sin x + y^3 = 4ax$ is

$\dfrac{dy}{dx} = \dfrac{y^3 + x^2 \cos x}{3xy^2}$

$\dfrac{dy}{dx} = \dfrac{y^3 - x^2 \cos x}{3xy^2}$

$\dfrac{dy}{dx} = \dfrac{y^3 - x^2 \cos x}{3xy}$

$\dfrac{dy}{dx} = \dfrac{y^3 - x^2 \cos x}{3x^2 y}$

MHT CET 2026 11th April Morning Shift

MCQ (Single Correct Answer)

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The order and degree of the differential equation $\sqrt{2 + \left(\dfrac{d^2 y}{dx^2}\right)^3} = \left(\dfrac{d^3 y}{dx^3}\right)^{5/2}$ respectively are

$2, 3$

$3, 5$

$3, 2$

$5, 3$

MHT CET 2026 11th April Morning Shift

MCQ (Single Correct Answer)

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The vector $\bar{a} + 3\bar{b}$ is perpendicular to $7\bar{a} - 5\bar{b}$ and the vector $\bar{a} - 4\bar{b}$ is perpendicular to $7\bar{a} - 2\bar{b}$. Then the angle between $\bar{a}$ and $\bar{b}$ is

$\dfrac{\pi}{2}$

$\dfrac{\pi}{4}$

$\dfrac{\pi}{6}$

$\dfrac{\pi}{3}$

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