1
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

The work done in turning a magnet of magnetic moment ' $M$ ' by an angle of $90^{\circ}$ from the meridian is ' $n$ ' times the corresponding Work done to turn it through an angle of $60^{\circ}$ where the value of ' $n$ ' is $\left(\cos 90^{\circ}=0, \cos 60^{\circ}=0.5\right)$

A
0.5
B
2
C
0.25
D
1
2
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

When magnetic flux changes from $6.5 \times 10^{-2} \mathrm{~Wb}$ to $11 \times 10^{-2} \mathrm{~Wb}$ and the change in current is 0.03 A , the coefficient of mutual inductance will be

A
1.0 H
B
1.2 H
C
1.5 H
D
1.8 H
3
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

At a place, the length of the oscillating simple pendulum is made $\frac{1}{4}$ times keeping amplitude same then the total energy will be

A
2 times
B
4 times
C
8 times
D
16 times
4
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+1
-0

125 small water drops of same size fall through air with constant velocity $4 \mathrm{~cm} / \mathrm{s}$. They coalesce to form a big drop. The terminal velocity of the big drop is

A
$0.5 \mathrm{~m} / \mathrm{s}$
B
$1 \mathrm{~m} / \mathrm{s}$
C
$1.5 \mathrm{~m} / \mathrm{s}$
D
$2.5 \mathrm{~m} / \mathrm{s}$
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