1
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

    $\int_{\frac{1}{2}}^2 \frac{1}{x} \operatorname{cosec}^{101}\left(x-\frac{1}{x}\right) \mathrm{d} x=$

A

0

B

1

C

$\frac{1}{4}$

D

$\frac{101}{2}$

2
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

Matrix A is non-singular matrix and $(A-3 I)(A-5 I)=0$, then $\frac{15}{8} A^{-1}=\ldots \ldots$

A

$\mathrm{I}-8 \mathrm{~A}$

B

$2 \mathrm{I}-\frac{1}{15} \mathrm{~A}$

C

$\mathrm{I}-\frac{1}{8} \mathrm{~A}$

D

$8 \mathrm{I}-15 \mathrm{~A}$

3
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If the plane $\frac{x}{2}+\frac{y}{3}+\frac{z}{6}=1$ cuts the co-ordinate axes at points $A, B, C$ respectively, then area of the triangle ABC is

A
$\sqrt{14}$ sq. units
B
$3 \sqrt{14}$ sq. units
C
$\frac{1}{\sqrt{14}}$ sq. units
D
$3 \sqrt{13}$ sq. units
4
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The number of positive integral solutions of $\tan ^{-1} x+\cos ^{-1}\left(\frac{y}{\sqrt{1+y^2}}\right)=\sin ^{-1}\left(\frac{3}{\sqrt{10}}\right)$ are

A
1
B
2
C
3
D
4

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