1
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

Let $\overline{\mathrm{a}}, \overline{\mathrm{b}}$ and $\overline{\mathrm{c}}$ be vectors of magnitude 2,3 and 4 respectively. If $\bar{a}$ is perpendicular to $(\overline{\mathrm{b}}+\overline{\mathrm{c}}), \overline{\mathrm{b}}$ is perpendicular to ( $\overline{\mathrm{c}}+\overline{\mathrm{a}}$ ) and $\overline{\mathrm{c}}$ is perpendicular to $(\bar{a}+\bar{b})$, then the magnitude of $\overline{\mathrm{a}}+\overline{\mathrm{b}}+\overline{\mathrm{c}}$ is

A

29

B

$\sqrt{28}$

C

$\sqrt{29}$

D

28

2
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\int \frac{\left(x^4+1\right)}{x\left(x^2+1\right)^2} d x=A \log |x|+\frac{B}{1+x^2}+c$, then $\mathrm{A}-\mathrm{B}$ is (where c is the constant of integration)

A

0

B

1

C

2

D

-1

3
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The angle between the tangents drawn from the point $(1,4)$ to the parabola $y^2=4 x$, is

A

$\frac{\pi}{6}$

B

$\frac{\pi}{2}$

C

$\frac{\pi}{3}$

D

$\frac{\pi}{4}$

4
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The solution for minimizing the function $\mathrm{z}=x+y$ under an L.P.P. with constraints $x+y \geq 2, x+2 y \leq 8, y \leq 3, x, y \geq 0$ is

A

at the point $(0,3)$

B

at the point $(8,0)$

C

at infinite number of points but bounded set

D

at unbounded set

MHT CET Papers

All year-wise previous year question papers