1
MHT CET 2025 23rd April Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$ \int \frac{(5 \sin \theta-2) \cos \theta}{\left(5-\cos ^2 \theta-4 \sin \theta\right)} d \theta= $$

A
$(\log 5 \sin \theta-2)+\mathrm{c}$, where c is the constant of integration
B
$5 \log (5 \sin \theta-2)-\frac{8}{(\sin \theta-2)}+\mathrm{c}$, where c is the constant of integration
C
$\log (5 \sin \theta-2)+\frac{8}{(\sin \theta-2)}+c$, where $c$ is the constant of integration
D
$\log (5 \sin \theta-2)+\frac{1}{(\sin \theta-2)}+c$, where $c$ is the constant of integration
2
MHT CET 2025 23rd April Evening Shift
MCQ (Single Correct Answer)
+2
-0

Number of switches in alternative equivalent simple circuit for the circuit is (are)

MHT CET 2025 23rd April Evening Shift Mathematics - Mathematical Reasoning Question 9 English
A
0
B
1
C
2
D
3
3
MHT CET 2025 23rd April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $0 \leqslant \cos ^{-1} x \leqslant \pi$ and $\frac{-\pi}{2} \leqslant \sin ^{-1} x \leqslant \frac{\pi}{2}$, then at $x=\frac{1}{5}$ the value of $\cos \left(2 \cos ^{-1} x+\sin ^{-1} x\right)$ is

A
$-\sqrt{\frac{24}{25}}$
B
$\sqrt{\frac{24}{25}}$
C
$\frac{\sqrt{24}}{25}$
D
$\frac{-\sqrt{24}}{25}$
4
MHT CET 2025 23rd April Evening Shift
MCQ (Single Correct Answer)
+2
-0
In a triangle ABC with usual notations if $b \sin C(b \cos C+c \cos B)=42$, then area of triangle $\mathrm{ABC}=$
A
42 sq. units
B
21 sq. units
C
24 sq. units
D
12 sq. units

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