1
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$ \int \sin ^5 x \mathrm{~d} x= $$

A
$\cos x+\frac{2}{3} \cos ^2 x-\frac{\cos ^5 x}{5}+\mathrm{c}$, where c is the constant of integration
B
$\quad \cos x+\frac{2}{3} \cos ^2 x+\frac{\cos ^5 x}{5}+\mathrm{c}$, where c is the constant of integration
C
$-\left(\cos x-\frac{2}{3} \cos ^2 x+\frac{\cos ^5 x}{5}+\mathrm{c}\right)$, where c is the constant of integration
D
$\cos x-\frac{2}{3} \cos ^2 x+\frac{\cos ^5 x}{5}+\mathrm{c}$, where c is the constant of integration
2
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If the angle between the planes $x-2 y+3 z-5=0$ and $x+\alpha y+2 z+7=0$ is $\cos ^{-1}\left(\frac{1}{14}\right)$ then the difference between the values of $\alpha$ is

A
$\frac{12}{11}$
B
$\frac{62}{55}$
C
$\frac{31}{11}$
D
$\frac{8}{5}$
3
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If the shortest distance between the lines $\frac{x-\mathrm{k}}{2}=\frac{y-4}{3}=\frac{\mathrm{z}-3}{4}$ and $\frac{x-2}{4}=\frac{y-4}{6}=\frac{\mathrm{z}-7}{8}$ is $\frac{13}{\sqrt{29}}$, then $\mathrm{k}=$

A
1
B
-1
C
2
D
-2
4
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The acute angle between the lines $x=-2+2 \mathrm{t}, y=3-4 \mathrm{t}, \mathrm{z}=-4+\mathrm{t}$ and $x=-2-\mathrm{t}, y=3+2 \mathrm{t}, \mathrm{z}=-4+3 \mathrm{t}$ is

A
$\quad \cos ^{-1}\left(\frac{1}{\sqrt{6}}\right)$
B
$\cos ^{-1}\left(\frac{1}{\sqrt{5}}\right)$
C
$\sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)$.
D
$\quad \cos ^{-1}\left(\frac{2}{\sqrt{6}}\right)$

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