1
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The direction cosines of the line $x-y+2 z=5$ and $3 x+y+z=6$ are

A
$\quad \frac{-3}{5 \sqrt{2}}, \frac{5}{5 \sqrt{2}}, \frac{4}{5 \sqrt{2}}$
B
$\quad \frac{3}{5 \sqrt{2}}, \frac{-5}{5 \sqrt{2}}, \frac{4}{5 \sqrt{2}}$
C
$\frac{3}{5 \sqrt{2}}, \frac{5}{5 \sqrt{2}}, \frac{4}{5 \sqrt{2}}$
D
$\quad \frac{3}{5 \sqrt{2}}, \frac{5}{5 \sqrt{2}}, \frac{-4}{5 \sqrt{2}}$
2
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

20 is divided into two parts so that the product of the cube of one part and the square of the other part is maximum, then these two parts are

A
15,5
B
16,4
C
12,8
D
14,6
3
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The acute angle between the diagonals of a parallelogram whose vertices are $\mathrm{A}(2,-1)$, $B(0,2), C(2,3)$ and $D(4,0)$ is

A
$\cot ^{-1} 2$
B
$\cot ^{-1}\left(\frac{1}{3}\right)$
C
$\tan ^{-1} 2$
D
$\tan ^{-1}\left(\frac{2}{3}\right)$
4
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The shortest distance between the line $y-x=1$ and the curve $x=y^2$ is

A
$\frac{3 \sqrt{2}}{8}$
B
$\frac{2 \sqrt{3}}{8}$
C
$\frac{3 \sqrt{2}}{5}$
D
$\frac{\sqrt{3}}{4}$

MHT CET Papers

All year-wise previous year question papers