MHT CET 2021 22th September Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2021 22th September Morning Shift

MCQ (Single Correct Answer)

-0

The Cartesian equation of a line is $$3 x+1=6 y-2=1-z$$, then its vector equation is

$$\bar{\mathrm{r}}=\left(\frac{-1}{3} \hat{\mathrm{i}}+\frac{1}{3} \hat{\mathrm{j}}+\hat{\mathrm{k}}\right)+\lambda(2 \hat{\mathrm{i}}-\hat{\mathrm{j}}-6 \hat{\mathrm{k}})$$

$$\bar{r}=(-\hat{i}+2 \hat{j}-\hat{k})+\lambda(3 \hat{i}+6 \hat{j}-\hat{k})$$

$$\bar{r}=\left(\frac{-1}{3} \hat{i}+\frac{1}{3} \hat{j}+\hat{k}\right)+\lambda(2 \hat{i}-\hat{j}+6 \hat{k})$$

$$\bar{\mathrm{r}}=\left(\frac{-1}{3} \hat{\mathrm{i}}+\frac{1}{3} \hat{\mathrm{j}}+\hat{\mathrm{k}}\right)+\lambda(2 \hat{\mathrm{i}}+\hat{\mathrm{j}}-6 \hat{\mathrm{k}})$$

MHT CET 2021 22th September Morning Shift

MCQ (Single Correct Answer)

-0

The position vector of the point of inersection of the medians of a triangle, whose vertices are $$A(1,2,3), B(1,0,3)$$ and $$C(4,1,-3)$$ is

$$6 \hat{i}+3 \hat{j}+3 \hat{k}$$

$$2 \hat{i}+\hat{j}+\hat{k}$$

$$3 \hat{i}+\hat{j}+\hat{k}$$

$$\hat{i}+\hat{j}+\hat{k}$$

MHT CET 2021 22th September Morning Shift

MCQ (Single Correct Answer)

-0

$$\int\limits_{ - \pi }^\pi {{{x\sin x} \over {1 + {{\cos }^2}x}}dx = } $$