1
KCET 2019
MCQ (Single Correct Answer)
+1
-0

$$\int \frac{1}{\sqrt{x}+x \sqrt{x}} d x=$$

A
$$\tan ^{-1} \sqrt{x}+C$$
B
$$2 \log (\sqrt{x}+1)+C$$
C
$$2 \tan ^{-1} \sqrt{x}+C$$
D
$$\frac{1}{2} \tan ^{-1} \sqrt{x}+C$$
2
KCET 2019
MCQ (Single Correct Answer)
+1
-0

$$\begin{aligned} & \int \frac{2 x-1}{(x-1)(x+2)(x-3)} d x \\ & \quad=A \log |x-1|+B \log |x+2|+C \log |x-3|+K \end{aligned}$$

Then $$A, B, C$$ are respectively

A
$$\frac{1}{6}, \frac{-1}{3}, \frac{1}{3}$$
B
$$\frac{-1}{6}, \frac{1}{3}, \frac{1}{3}$$
C
$$\frac{-1}{6}, \frac{-1}{3}, \frac{1}{2}$$
D
$$\frac{1}{6}, \frac{1}{3}, \frac{1}{5}$$
3
KCET 2019
MCQ (Single Correct Answer)
+1
-0

$$\int_\limits0^2\left[x^2\right] d x=$$

A
$$5-\sqrt{2}+\sqrt{3}$$
B
$$5-\sqrt{2}-\sqrt{3}$$
C
$$-5-\sqrt{2}-\sqrt{3}$$
D
$$5+\sqrt{2}-\sqrt{3}$$
4
KCET 2019
MCQ (Single Correct Answer)
+1
-0

$$\int_\limits0^1 \sqrt{\frac{1+x}{1-x}} d x=$$

A
$$\frac{\pi}{2}$$
B
$$\frac{\pi}{2}-1$$
C
$$\frac{1}{2}$$
D
$$\frac{\pi}{2}+1$$
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