1
KCET 2019
MCQ (Single Correct Answer)
+1
-0

The equation of the curve passing through the point $$(1,1)$$ such that the slope of the tangent at any point $$(x, y)$$ is equal to the product of its co-ordinates is

A
$$2 \log y=x^2-1$$
B
$$2 \log x=y^2-1$$
C
$$2 \log x=y^2+1$$
D
$$2 \log y=x^2+1$$
2
KCET 2019
MCQ (Single Correct Answer)
+1
-0

Foot of the perpendicular drawn from the point $$(1,3,4)$$ to the plane $$2 x-y+z+3=0$$ is

A
$$(1,2-3)$$
B
$$(-1,4,3)$$
C
$$(-3,5,2)$$
D
$$(0,-4,-7)$$
3
KCET 2019
MCQ (Single Correct Answer)
+1
-0

Acute angel between the line $$\frac{(x-5)}{2}=\frac{y+1}{-1}=\frac{z+4}{1}$$ and the plane $$3 x-4 y-z+5=0$$ is

A
$$\cos ^{-1}\left(\frac{5}{2 \sqrt{3}}\right)$$
B
$$\cos ^{-1}\left(\frac{9}{\sqrt{364}}\right)$$
C
$$\sin ^{-1}\left(\frac{5}{2 \sqrt{13}}\right)$$
D
$$\sin ^{-1}\left(\frac{9}{\sqrt{364}}\right)$$
4
KCET 2019
MCQ (Single Correct Answer)
+1
-0

The distance of the point $$(1,2,1)$$ from the line $$\frac{x-1}{2}=\frac{y-2}{1}=\frac{z-3}{2}$$ is.

A
$$\frac{\sqrt{5}}{3}$$
B
$$\frac{2 \sqrt{3}}{5}$$
C
$$\frac{20}{3}$$
D
$$\frac{2 \sqrt{5}}{3}$$
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