1
KCET 2019
MCQ (Single Correct Answer)
+1
-0

If $$A=\left[\begin{array}{ll}1 & 3 \\ 4 & 2\end{array}\right], B=\left[\begin{array}{cc}2 & -1 \\ -1 & 2\end{array}\right]$$, Then $$\left|A B B^{\prime}\right|=$$

A
100
B
50
C
250
D
$$-$$250
2
KCET 2019
MCQ (Single Correct Answer)
+1
-0

If the value of a third order determinant is 16, then the value of the determinant formed by replacing each of its elements by its cofactor is

A
256
B
96
C
16
D
48
3
KCET 2019
MCQ (Single Correct Answer)
+1
-0

$$\int x^3 \sin 3 x d x=$$

A
$$-\frac{x^3 \cdot \cos 3 x}{3}+\frac{x^2 \sin 3 x}{3}+\frac{2 x \cos 3 x}{9} -\frac{2 \sin 3 x}{27}+C$$
B
$$-\frac{x^3 \cdot \cos 3 x}{3}-\frac{x^2 \sin 3 x}{3}+\frac{2 x \cos 3 x}{9} -\frac{2 \sin 3 x}{27}+C$$
C
$$-\frac{x^3 \cdot \cos 3 x}{3}+\frac{x^2 \sin 3 x}{3}-\frac{2 x \cos 3 x}{9} -\frac{2 \sin 3 x}{27}+C$$
D
$$\frac{x^3 \cdot \cos 3 x}{3}+\frac{x^2 \sin 3 x}{3}-\frac{2 x \cos 3 x}{9} -\frac{2 \sin 3 x}{27}+C$$
4
KCET 2019
MCQ (Single Correct Answer)
+1
-0

The area of the region above $$X$$-axis included between the parabola $$y^2=x$$ and the circle $$x^2+y^2=2 x$$ in square units is

A
$$\frac{2}{3}-\frac{\pi}{4}$$
B
$$\frac{\pi}{4}-\frac{3}{2}$$
C
$$\frac{\pi}{4}-\frac{2}{3}$$
D
$$\frac{3}{2}-\frac{\pi}{4}$$
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