1
KCET 2019
MCQ (Single Correct Answer)
+1
-0

The sides of an equilateral triangle are increasing at the rate of $$4 \mathrm{~cm} / \mathrm{sec}$$. The rate at which its area is increasing, when the side is $$14 \mathrm{~cm}$$

A
$$42 \mathrm{~cm}^2 / \mathrm{sec}$$
B
$$10 \sqrt{3} \mathrm{~cm}^2 / \mathrm{sec}$$
C
$$14 \mathrm{~cm}^2 / \mathrm{sec}$$
D
$$14 \sqrt{3} \mathrm{~cm}^2 / \mathrm{sec}$$
2
KCET 2019
MCQ (Single Correct Answer)
+1
-0

The value of $$\sqrt{24.99}$$ is

A
5.001
B
4.999
C
4.897
D
4.899
3
KCET 2019
MCQ (Single Correct Answer)
+1
-0

$$\int_\limits{-3}^3 \cot ^{-1} x d x=$$

A
$$6\pi$$
B
$$3\pi$$
C
3
D
0
4
KCET 2019
MCQ (Single Correct Answer)
+1
-0

$$\int \frac{1}{\sqrt{x}+x \sqrt{x}} d x=$$

A
$$\tan ^{-1} \sqrt{x}+C$$
B
$$2 \log (\sqrt{x}+1)+C$$
C
$$2 \tan ^{-1} \sqrt{x}+C$$
D
$$\frac{1}{2} \tan ^{-1} \sqrt{x}+C$$
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