1
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Arrange the following free radicals in the increasing order of their stability:

A B C D
COMEDK 2025 Morning Shift Chemistry - General Organic Chemistry Question 1 English 1 COMEDK 2025 Morning Shift Chemistry - General Organic Chemistry Question 1 English 2 COMEDK 2025 Morning Shift Chemistry - General Organic Chemistry Question 1 English 3 COMEDK 2025 Morning Shift Chemistry - General Organic Chemistry Question 1 English 4

A
$\mathrm{A}<\mathrm{B}<\mathrm{D}<\mathrm{C}$
B
$\mathrm{C}<\mathrm{D}<\mathrm{B}<\mathrm{A}$
C
$\mathrm{C}<\mathrm{B}<\mathrm{D}<\mathrm{A}$
D
$\mathrm{A}<\mathrm{B}<\mathrm{C}<\mathrm{D}$
2
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
If X is a haloalkane with a single Chlorine atom per molecule and the percentage of Cl is 55 , what would be the number of Cl atoms present in 0.1 g of the haloalkane? Atomic mass of $\mathrm{Cl}=35.5 \mathrm{~g} / \mathrm{mol}$
A
$6.022 \times 10^{22}$
B
$1.2044 \times 10^{21}$
C
$9.328 \times 10^{20}$
D
$9.329 \times 10^{23}$
3
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
For a reaction $\mathrm{X}_2(\mathrm{l})+\mathrm{Y}_2(\mathrm{~g}) \leftrightharpoons 2 \mathrm{XY}(\mathrm{g})$, the $\Delta \mathrm{H}^0$ and $\Delta \mathrm{S}^0$ are $+29.3 \mathrm{~kJ} / \mathrm{mol}$ and $104.1 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ respectively at 298 K . Find the free energy change in $\mathrm{kJ} / \mathrm{mol}$.
A
0.6
B
2.04
C
5.2
D
1.72
4
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
Which one of the following reactions does not give the correct combination of reactants and the major products formed in the reaction?
A
$\mathrm{CH}_3-\mathrm{CO}-\mathrm{CH}_3+\mathrm{NH}_2-\mathrm{NH}-\mathrm{CO}-\mathrm{NH}_2($ weakly basic $) \rightarrow\left(\mathrm{CH}_3\right)_2 \mathrm{C}=\mathrm{N}-\mathrm{NH}-\mathrm{CO}-\mathrm{NH}_2$
B
$\mathrm{CH}_3 \mathrm{CHO}+2 \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}($ dry HCl gas $) \leftrightharpoons \mathrm{CH}_3-\mathrm{CH}-\left(\mathrm{OC}_2 \mathrm{H}_5\right)_2$
C
$\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CN}$ $\xrightarrow[\text { (ii). } \mathrm{H}_2 \mathrm{O}]{\text { (i). DIBAL-H }} \mathrm{CH}_3-\left(\mathrm{CH}_2\right)_4-\mathrm{CHO}$
D
$\mathrm{C}_6 \mathrm{H}_5-\mathrm{CO}-\mathrm{CH}_3+\mathrm{I}_2+\mathrm{Na}_2 \mathrm{CO}_3($ Heat $) \rightarrow \mathrm{CHI}_3+\mathrm{C}_6 \mathrm{H}_5 \mathrm{COO}^{--}$
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