1
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
Which one of the following reactions does not give the correct combination of reactants and the major products formed in the reaction?
A
$\mathrm{CH}_3-\mathrm{CO}-\mathrm{CH}_3+\mathrm{NH}_2-\mathrm{NH}-\mathrm{CO}-\mathrm{NH}_2($ weakly basic $) \rightarrow\left(\mathrm{CH}_3\right)_2 \mathrm{C}=\mathrm{N}-\mathrm{NH}-\mathrm{CO}-\mathrm{NH}_2$
B
$\mathrm{CH}_3 \mathrm{CHO}+2 \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}($ dry HCl gas $) \leftrightharpoons \mathrm{CH}_3-\mathrm{CH}-\left(\mathrm{OC}_2 \mathrm{H}_5\right)_2$
C
$\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CN}$ $\xrightarrow[\text { (ii). } \mathrm{H}_2 \mathrm{O}]{\text { (i). DIBAL-H }} \mathrm{CH}_3-\left(\mathrm{CH}_2\right)_4-\mathrm{CHO}$
D
$\mathrm{C}_6 \mathrm{H}_5-\mathrm{CO}-\mathrm{CH}_3+\mathrm{I}_2+\mathrm{Na}_2 \mathrm{CO}_3($ Heat $) \rightarrow \mathrm{CHI}_3+\mathrm{C}_6 \mathrm{H}_5 \mathrm{COO}^{--}$
2
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Match the coordination compounds in Column I having the given type of hybridisation of $\mathrm{M}^{\mathrm{n}+}$ ion and magnetic moment as given in Column II.

Coordination compounds Hybridisation & Magnetic nature
A. $\mathrm{Ni}(\mathrm{CO})_4$ P. $\mathrm{sp}^3, \quad \mu=5.92 \mathrm{BM}$
B. $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ Q. $\mathrm{sp}^3, \quad \mu=2.84 \mathrm{BM}$
C. $\left[\mathrm{Ni}(\mathrm{Cl})_4\right]^{2-}$ R. $\mathrm{sp}^3, \quad \mu=0$
D. $\left[\mathrm{MnBr}_4\right]^{2-}$ S. $\mathrm{dsp}^2, \quad \mu=0$

A
$\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P}$
B
$A=S \quad B=R \quad C=P \quad D=Q$
C
$\mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{P} \quad \mathrm{C}=\mathrm{R} \quad \mathrm{D}=\mathrm{Q}$
D
$\mathrm{A}=\mathrm{Q} \quad \mathrm{B}=\mathrm{P} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{R}$
3
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
The EMF of the cell $\mathrm{Al} / \mathrm{Al}^{3+}(0.01 \mathrm{M}) \| \mathrm{Fe}^{2+}(0.02 \mathrm{M}) / \mathrm{Fe}$ is 1.209 V . The EMF of the cell can be increased by
A
increasing the concentration of $\mathrm{Al}^{3+}$ and $\mathrm{Fe}^{2+}$
B
increasing the concentration of $\mathrm{Al}^{3+}$
C
increasing the concentration of $\mathrm{Fe}^{2+}$
D
decreasing the concentration of $\mathrm{Al}^{3+}$ and $\mathrm{Fe}^{2+}$
4
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0

An unsaturated hydrocarbon $[\mathrm{A}]$ undergoes the following series of reactions. Identify $[\mathrm{A}]$.

COMEDK 2025 Morning Shift Chemistry - Hydrocarbons Question 1 English

A
Propyne
B
But-2-yne
C
But-1-yne
D
But-2-ene
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