1
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
The conductivity of 0.01 M solution of $\mathrm{CH}_3 \mathrm{COOH}$ at 298 K is $1.65 \times 10^{-4} \mathrm{Scm}^{-1}$ What is the $\mathrm{pK}_{\mathrm{a}}$ value of the acid if $\lambda^0\left(\mathrm{H}^{+}\right)$and $\lambda^0\left(\mathrm{CH}_3 \mathrm{COO}\right)^{-1}$ are $349.1 \mathrm{Scm}^2 \mathrm{~mol}^{-1}$ and $40.9 \mathrm{Scm}^2 \mathrm{~mol}^{-1}$ respectively?
A
4.73
B
1.87
C
3.47
D
2.95
2
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two statements, one Assertion (A) and the other Reason (R) are given. Choose the correct option.

Assertion: 2-aminoethanoic acid and p-aminobenzene sulphonic acid can exist as Zwitter ions while p-aminobenzoic acid cannot.

Reason: When the acid group is a relatively strong proton donor and the $-\mathrm{NH}_2$ group is sufficiently basic it can accept a $\mathrm{H}^{+}$ion from the acid group to form the dipolar ion.

A
Both A and R are correct and R is the correct explanation of A .
B
A is correct but R is wrong.
C
A is wrong but R is correct.
D
Both A and R are correct but R is not the correct explanation of A .
3
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0
$\mathrm{X} \rightarrow 2 \mathrm{Y}$ is a first order reaction where $1.0 \mathrm{~mol} / \mathrm{L}$ of the reactant yields $0.4 \mathrm{~mol} / \mathrm{L}$ of Y in 200 minutes. Calculate the half-life period of the reaction in minutes.
A
151.24
B
203.69
C
620.96
D
271.34
4
COMEDK 2025 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Match the reactions of Glucose given in Column I with the major product formed in the reaction as in Column II.

Column I - Reactions Column II - Major product
A. $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6+\mathrm{HI}$ (Heat) P. $\mathrm{HOOC}-(\mathrm{CHOH})_4-\mathrm{COOH}$
B. $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6+\mathrm{Br}_2(\mathrm{aq})$ Q. $\mathrm{CH}_3-\left(\mathrm{CH}_2\right)_4-\mathrm{CH}_3$
C. $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6+$ Conc. $\mathrm{HNO}_3$ R. $\mathrm{NH}_4 \mathrm{O}-\mathrm{OC}-(\mathrm{CHOH})_4-\mathrm{CH}_2 \mathrm{OH}$
D. $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6+2\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right] \mathrm{OH}$ S. $\mathrm{HOOC}-(\mathrm{CHOH})_4-\mathrm{CH}_2 \mathrm{OH}$

A
$\mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P}$
B
$A=P \quad B=S \quad C=Q \quad D=R$
C
$\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{P} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{Q}$
D
$\mathrm{A}=\mathrm{Q} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{R}$
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