AP EAPCET 2024 - 22th May Evening Shift | AP EAPCET Year Wise Previous Years Questions

AP EAPCET 2024 - 22th May Evening Shift

MCQ (Single Correct Answer)

-0

In the reaction sequence $Y$ is

$$ \mathrm{CH}_3 \mathrm{CO}_2 \mathrm{H} \xrightarrow[(2) \Delta]{(1) \mathrm{NH}_3} P \xrightarrow{\mathrm{Br} / \mathrm{NaOH}} Y $$

a primary amine with same number of carbons as in P.

a primary amine with one carbon less than in $P$.

a secondary amine with same number of carbons as in P

a secondary amine with one carbon less than in P.

AP EAPCET 2024 - 22th May Evening Shift

MCQ (Single Correct Answer)

-0

In the equation $\left(p+\frac{a}{V^2}\right)(V-b)=R T$, where $p$ is pressure, $V$ is volume, $T$ is temperature, $R$ is universal gas constant, $a$ and $b$ are constants. The dimensions of $a$ are

$\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]$

$\left[M L^5 T^{-2}\right]$

$\left[M^0 L^3 T^0\right]$

$\left[M L^3 \mathrm{~T}^{-2}\right]$

AP EAPCET 2024 - 22th May Evening Shift

MCQ (Single Correct Answer)

-0

A particle starts from rest and moves in a straight line. It travels a distance $2 L$ with uniform acceleration and then moves with a constant velocity a further distance of $L$. Finally, it comes to rest after moving a distance of $3 L$ under uniform retardation. Then, the ratio of average speed to the maximum speed $\left(\frac{v}{v_m}\right)$ of the particle is

$\frac{6}{11}$

$\frac{7}{11}$

$\frac{5}{11}$

$\frac{2}{11}$

AP EAPCET 2024 - 22th May Evening Shift

MCQ (Single Correct Answer)

-0

A boy throws a ball with a velocity $v_0$ at an angle $\alpha$ to the ground. At the same time he starts running with uniform velocity to catch the ball before it hits the ground. To achieve this, he should run with a velocity of

$v_0 \cos \alpha$

$v_0 \sin \alpha$

$v_0 \tan \alpha$

$\sqrt{v_0{ }^2 \tan \alpha}$

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