The rake angle of a cutting tool is $${15^ \circ }$$, shear angle $${45^ \circ }$$ and cutting velocity $$35$$ $$m/min$$. What is the velocity of chip along the tool face?

A batch of $$500$$ jobs of diameter $$50$$ $$mm$$ and length $$100$$ $$mm$$ is to be turned at $$200$$ $$rev/min$$ and feed $$0.2$$ $$mm/rev.$$

The number of components per tool life

A batch of $$500$$ jobs of diameter $$50$$ $$mm$$ and length $$100$$ $$mm$$ is to be turned at $$200$$ $$rev/min$$ and feed $$0.2$$ $$mm/rev.$$

Applying Taylor's equation $$V{T^{0.25}} = 160,$$ the tool life in minutes is

A $$\phi $$ $$40$$ $$mm$$ job is subjected to orthogonal turning by a $$ + {10^ \circ }$$ rake angle tool at $$500$$ $$rev/min.$$ By direct measurement during the cutting operation, the shear angle was found equal to $${25^ \circ }.$$

If the friction angle at the tool-chip interface is $${58^ \circ }$$ $$10'$$ and the cutting force components measured by a dynamometer are $$600$$ $$N$$ and $$200$$ $$N$$, the power loss due to friction (in $$kNm/min$$) is approximately