A batch of $$500$$ jobs of diameter $$50$$ $$mm$$ and length $$100$$ $$mm$$ is to be turned at $$200$$ $$rev/min$$ and feed $$0.2$$ $$mm/rev.$$

Applying Taylor's equation $$V{T^{0.25}} = 160,$$ the tool life in minutes is

The following data relate to an orthogonal turning process:
$$\,\,\,\,\,\,\,\,\,\,\,$$Back rake angle $$=15deg,$$
$$\,\,\,\,\,\,\,\,\,\,\,$$Width of cut $$=2mm,$$
$$\,\,\,\,\,\,\,\,\,\,\,$$Chip thickness $$=0.4mm,$$
$$\,\,\,\,\,\,\,\,\,\,\,$$Feed rate $$=0.2mm/rev.$$

The shear angle is

The rake angle of a cutting tool is $${15^ \circ }$$, shear angle $${45^ \circ }$$ and cutting velocity $$35$$ $$m/min$$. What is the velocity of chip along the tool face?

A $$\phi $$ $$40$$ $$mm$$ job is subjected to orthogonal turning by a $$ + {10^ \circ }$$ rake angle tool at $$500$$ $$rev/min.$$ By direct measurement during the cutting operation, the shear angle was found equal to $${25^ \circ }.$$

The velocity (in $$m/min$$) with which the chip flows on the tool face is